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  In this page, we are going to analysis the important topic or theorem in Complex Analysis.    Fundamental Theorem of Algebra in Complex Analysis is a very important topic to understand that can enhance your Higher Mathematics knowledge. Fundamental Theorem of Algebra in Complex Analysis Statement: If f(z) =  a 0 z n + a 1 z n-1 + ... + a n , a 0 ≠ 0 be a polynomial in z, then f(z) = 0 has at least one root in z-plane. Proof: If possible, let f(z) = 0 has no root in z-plane. Therefore, f(z)  ≠ 0 for any value of z in z-plane. We define, because, f(z) is analytic and f(z)  ≠ 0 therefore, F(z) is analytic for all values of z. Also, |F(z)| --> 0 as |z| -->  ∞  therefore, F(z) is bounded therefore, By Liouville's Theorem, F(z) is constant. ⇒ f(z) is constant, which is contradiction [because, f(z) is not constant polynomial] therefore, f(z) = 0 has at least one root in z-plane. Explanation in YouTube:

Complex Analysis Questions Complex Analysis Q. Represent the complex number z = 1 + i√3 in the polar form. Sol. 1 + i√3 = r(cos θ + isinθ) ∴ rcosθ = 1 ...(1) and rsinθ = √3 ...(2) Squring and adding (1) and (2), we get, r 2 (cos 2 θ + sin 2 θ) = 1 + 3 r 2 = 4 ⇒ r = 2 ∴ form (1) and (2), cosθ = 1/2, sinθ = √3/2 ∴ θ = π/3 ∴ z = 1 + i√3 = 2(cos π/3 + isin π/3) The complex number z= 1 + √3 is represented by P(2,π/3) into polar.

Triangle Inequality in Complex Analysis What is the Triangle Inequality? In Complex Analysis, it states that any two complex number z 1 and z 2 , the equality holds: |z 1 + z 2 | ≤ |z 1 | + |z 2 | Here, |z| denotes the modulus of the complex number, and the modulus of complex number z = x + y i , where x is the real number and y i is the imaginary number. So, in complex analysis is defined as, |z| = √(x 2 + y 2 ) What is the Triangle Inequality number theory? In Number Theory, the Triangle Inequality is discussed in the context of the absolute value function over the integers or the real number. It states that for any real number a and b, the Inequality holds: |a + b| ≤ |a| + |b| Proof of Triangle Inequality in Number Theory. Wha...

Triangle Inequality in Number Theory Triangle Inequality in Number Theory For any real numbers a and b , the Triangle Inequality states: |a + b| ≤ |a| + |b| Proof We will consider different cases based on the signs of a and b : Case 1: a ≥ 0 and b ≥ 0 |a + b| = a + b = |a| + |b| Case 2: a ≥ 0 and b < 0 (or vice versa) If a + b ≥ 0, then: |a + b| = a + b ≤ a - b = |a| + |b| If a + b < 0, then: |a + b| = -(a + b) = -a - b = |a| + |b| Case 3: a < 0 and b < 0 |a + b| = -(a + b) = -a - b = |a| + |b| Algebraic Proof Using the definition of absolute values: |a + b| 2 ≤ (|a| + |b|) 2 |a + b| 2 = (a + b) 2 = a 2 + 2ab + b 2 (|a| + |b|) 2 = |a| 2 + 2|a||b| + |b| 2 Since |a| 2 = a 2 and |b| 2 = b 2 : a 2 + 2ab + b 2 ≤ a 2 + 2|a||b| + b 2 ...

Cauchy-Riemann equations Proof of Cauchy-Riemann Equation