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Show that the following pair of functions are linearly independent yet Wronskian vanishes on the given interval

Linear Independence and Wronskian Show that the following pair of functions are linearly independent yet their Wronskian vanishes on the given interval $$f_{1}=\begin{cases}x^{2},x\ge0\\ 0,x Sol. The given functions are $$f_{1}=\begin{cases}x^{2},x\ge0\\ 0,x We want to prove that $$f_{1}$$, $$f_{2}$$ are L.I. For this purpose, we shall show that ...(1) if $$c_{1}f_{1}+c_{2}f_{2}=0$$ for all $$x\in\mathbb{R}$$, then each of $$c_{1}$$, $$c_{2}$$ is zero. For this purpose, we use $$x=-1.1$$. Now $$f_{1}(1)=1$$, $$f_{2}(1)=0$$, and $$f_{1}(-1)=0$$, $$f_{2}(-1)=1$$. Substituting these values in (1), we get, $$c_{1}\cdot1+c_{2}\cdot0=0\Rightarrow c_{1}=0$$ and $$c_{1}\cdot0+c_{2}\cdot1=0\Rightarrow c_{2}\rightarrow0$$ We have $$c_{1}f_{1}+c_{2}f_{2}=0\Rightarrow c_{1\frac{3}{3}}=c_{2}=0$$ Hence $$f_{1}$$, $$f_{2}$$ are linearly independent on the given interval. Now, we find the Wronskian of the given functions. Two cases arise. Case I. When $$x\...

Show by Wronskian that x, x^3, x^4 are Linearly Independent if x is non-zero.

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  Let          f1(x) = x,     f2(x) = x^3,     f3(x) = x^4                  f'1(x) = 1,    f'2(x) = 3x^2  f'(x) = 4x^3                  f"1(x) = 0,   f"2(x) = 6x,    f"3(x) = 12x^2 W( f 1, f 2, f 3) =                     =  Taking x common form 1st Row                =                =  Now,                                         = x(24x^4 - 18x^4)                                        = 6x^5 which is not equal to o Therefore...