Solve the Non-Exact differential equation (x^2 + y^2 + 2x)dx + 2ydy = 0 | Study With Nitin

Solution of (x² + y² 2xy)dx +2ydy=0 is a non-exact differential EQUATION 

In this page, now you have to see that the Question (x^2 + y^2 + 2x)dx + 2ydy = 0 is the non exact differential equation and here is the solution of this question. In our website you have to see that we are updated higher Maths question and videos on it, that why you can not confuse for understand the question.

Here, we find the integrating factor of this equation and also we solve the full question. This is the differential equation equation and we will solve it.

SOLUTION:










For Understanding the Question







F&Qs for (x² + y² 2xy)dx +2ydy=0 

Q. Where the question is taken ?
Ans: Differential Equation.
Q. What is the solution of (x^2 + y^2 + 2x)dx + 2ydy = 0 ?
Ans: Sol. is e^x(x^2 + y^2) = c.
Q. Which formula using here to find the solution ?
Ans: integral Mdx + integral (terms in N not contaning x)dy = c
Here, Integral Mdx,
y is constant.

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